Problem for the homework 3, chapter 3.
You drive your car 5.0 km due East at 35km/hr, and suddenly
realize that you forgot your wallet. So,
you return home, driving West at 40 km/hr, and upon arrival spend 10 minutes
looking for it, and finally go back on the road for a total of 57.0 km due East. If your average speed was 40 km/hr for the
whole journey, what was your average speed on your last leg?
a)46 km/hr
b)49 km/hr
c)35 km/hr
d) 40 km/hr
Solution
To East:
x1=5km
V1=35 km/h
t1=x1/v1=(5km)/( 35 km/h)=
1/7 h
Back to home, driving West:
V2=40 km/h
t2=x1/V2=(5 km)/(40 km/h)=1/8
h
Looking time t3=10 minutes = 1/6 h
Distance of the last leg due Est = 57 km
Distance Total (The total length of the total pass) =
5km+5km+57km=67km
Vaverage total=40km/h
Total time = (Distance Total)/ Vaverage total
= (67km)/(40 km/h)
The time on the last leg = Total time – t1-t2-t3
= (67km)/(40 km/h) – 1/7 h – 1/8 h – 1/6 h
The average speed on the last leg = (Distance of the last leg)/(
The time on the last leg) = 57km/ ((67km)/(40 km/h) – 1/7 h – 1/8 h – 1/6 h)
Expression to the Google calculator:
57 km/ ((67 km)/(40 km/hour) – 1/7 hour – 1/8 hour – 1/6 hour) in km/hour
57 km/ ((67 km)/(40 km/hour) – 1/7 hour – 1/8 hour – 1/6 hour) in km/hour
Google result: 45.950096 km / hour
Answer: a) 46 km/h
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