Problem for the homework 3, chapter 3.
You drive your car 5.0 km due East at 35km/hr, and suddenly
realize that you forgot your wallet. So,
you return home, driving West at 40 km/hr, and upon arrival spend 10 minutes
looking for it, and finally go back on the road for a total of 57.0 km due East. If your average speed was 40 km/hr for the
whole journey, what was your average speed on your last leg?
a)46 km/hrb)49 km/hr
c)35 km/hr
d) 40 km/hr
2) Algebra-Oriented Solution
To East:x1=5km
V1=35 km/h
t1=x1/V1
Back to home, driving West:
V2=40 km/h
t2=x1/V2
Looking time t3=10 minutes = 1/6 h
Distance of the last leg due East x4 = 57 km
Distance Total (The total length of the total road pass) d = 2x1+x4
Vaverage total=VA = 40km/h
V4=?
Total time = (Distance Total)/ Vaverage total = d/VA= (2x1+x4)/ VA
Total time= t1+t2+t3+t4 = x1/V1 + x1/V2 + t3 + x4/V4
(2x1+x4)/ VA = x1/V1 + x1/V2 + t3 + x4/V4
x4/V4 = (2x1+x4)/ VA - x1/V1 - x1/V2 - t3
V4/ x4 = 1/( (2x1+x4)/ VA - x1/V1 - x1/V2 - t3 )
V4 = x4 /( (2x1+x4)/ VA - x1/V1 - x1/V2 - t3 )
Mathematical Expression for Calculation:
x1=5km, V1=35 km/h, V2=40
km/h, t3=10 minutes, x4 = 57 km, VA = 40km/h
V4 = x4
/( (2x1+x4)/ VA
- x1/V1 - x1/V2 - t3 )
Expression to the Google calculator:
57km /( (2* 5km+57km)/ 40 km/h – 5km/35km/h – 5km/40km/h - 10minutes ) in km/h
57km /( (2* 5km+57km)/ 40 km/h – 5km/35km/h – 5km/40km/h - 10minutes ) in km/h
Google result: 45.950096 km / hour
Answer: a) 46 km/h
No comments:
Post a Comment