The 2-dimensional object of art shown in the figure is held in display at a museum by support S and rope R. Support S is on the floor and rope R is attached to the ceiling. The coefficient of static friction between the object and support S is 0.5. If the angle, θ has its maximum value such that the object remains in static equilibrium on the support, what is the magnitude of the normal force N the support exerts on the object? The object's mass is 25 kg and the distances from object's center of mass, CM, to its contact points with the support and the rope are s = 35 cm and r = 55 cm, respectively.
μ=0.5; m=25kg; s=35cm; r=55cm
fₛ≤μN
fₛ=μN (maximum)
fₛ=Tsinθ
N+Tcosθ=mg
N∙s∙sin30°+fₛ∙s∙cos30°=rTcosθ
N∙s∙sin30°+μN∙s∙cos30°=r(mg-N)
N∙s∙sin30°+μN∙s∙cos30°=rmg-rN
N∙s∙sin30°+μN∙s∙cos30°+rN=rmg
N∙(s∙sin30°+μ∙s∙cos30°+r)=rmg
N∙=rmg/(s∙sin30°+μ∙s∙cos30°+r)
Calculation: 55*25*9.81/(35*sin(30degree)+0.5*35*cos(30degree)+55cm)=153.88376691
N=154 N
μ=0.5; m=25kg; s=35cm; r=55cm
fₛ≤μN
fₛ=μN (maximum)
fₛ=Tsinθ
N+Tcosθ=mg
N∙s∙sin30°+fₛ∙s∙cos30°=rTcosθ
N∙s∙sin30°+μN∙s∙cos30°=r(mg-N)
N∙s∙sin30°+μN∙s∙cos30°=rmg-rN
N∙s∙sin30°+μN∙s∙cos30°+rN=rmg
N∙(s∙sin30°+μ∙s∙cos30°+r)=rmg
N∙=rmg/(s∙sin30°+μ∙s∙cos30°+r)
Calculation: 55*25*9.81/(35*sin(30degree)+0.5*35*cos(30degree)+55cm)=153.88376691
N=154 N
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